Q: How many significant figures in 2.8 x 10.5?

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0.0047

0.0805

6.353 (as the 28 is closer to three than two)

Speed = distance / time = 55 / 28 = 1.96 m/s (correct to 3 significant figures)

Exactly 3.75 times.

Related questions

0.0047

0.0805

6.353 (as the 28 is closer to three than two)

Speed = distance / time = 55 / 28 = 1.96 m/s (correct to 3 significant figures)

Exactly 3.75 times.

The GCF of 28 and 105 is 7.

28 is 100(28/63) = 44 percent, to the justified number of significant digits.

It is: 7

It is 7.

what is the greatest common factor of 28 49 and 105

28

The LCM is: 420