0
None.
Whatever number you substitute for 'x', 0x will always be 0,
and the equation will always become [ 0 = 4 ].
No value of 'x' can make [ 0 = 4 ]. There is no solution.
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What are the solutions for the quadratic equation x2 minus 21x equals 72?
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
What are the roots of the quadratic equation x2 - 14x plus 45 equals 0?
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
What if -x plus x equals 0x?
This is always true! According to the Additive Inverse Axiom -X+X always equals 0 which is equivalent to 0X.
Why does x equal to 8 and 0 in x2 equals 8x?
x2 = 8xx2- 8x = 0x(x - 8) = 0x = 0 ;x - 8 = 0x = 8
What is x if x plus -2.5 plus 6.8 equals 0?
x+(-2.5)+6.8=0x+(-2.5+6.8)=0x+(4.3)=0x+4.3=0Subtract 4.3 from both sides and you get:x= -4.3
What are the solutions of the equation x2-x equals 30?
-28
How do you know when an equations has infinitly many solutions?
An equation must have 1, 0, or infinitely many solutions. So if you find 1 and there is another, you have know it has infinitely many. For example. 0x+2=2 I solve this and the equations become 0x=0 Now, 1 is a solutions, but so is 2. I now know there are infinitely many. How about 0x+2=3. No solution and 2x+2=4, has one solution. I put those two here so you might try other numbers and see that they have no solutions and one solution. A special type of equation known as an identity is an equation that holds for all numbers. This means it has infinitely many solutions.
What are the solutions for the quadratic equation x2 minus 21x equals 72?
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
What does 0x equals 17 mean?
There is no value of x that satisfies the equation. You may be missing an operator (+. - sign).
How do you solve this equation x3 plus 13x2 equals -22x?
x3+13x2=-22xadd 22x to both sides:x3+13x2+22x=0now factor:x(x2+13x+22)=0x(x+11)(x+2)=0x=0x+11=0x+2=0Therefore the solution to this equation is x=0, x=-11, x=-2
What is the solution for the equation x plus 1 equals x plus 2?
x+1=x+2 x=1+2+x 0x=1+2 0x=3 0x=/=3 (=/= means does not equal) so there is no solution
What is the solution of x2-x-4 equals 0?
have to put it was 2x and not x2--back to the problem--2x-x-4=0x=4* * * * *True, but the question, in all likelihood WAS x2 - x - 4 = 0and the solutions to that equation are -1.561553 and 2.561553
What are the roots of the quadratic equation x2 - 14x plus 45 equals 0?
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
What is the equation whose solutions are x equals 2 over 3 and x equals 5 over 7 showing work?
x-2/3 = 0x - 5/7 = 0(x-2/3)(x-5/7) = 0x^2 -2/3(x) -5/7(x) + 10/21 = 0x^2 -14/21(x) - 15/21(x) +10/21 = 0x^2 -29/21(x) +10/21 = 0Another Answer:-If: x = 2/3 and x = 5/7Then: (3x-2)(7x-5) = 0Multiplying out the brackets: 21x2-29x+10 = 0 which is the equation.Check using the quadratic equation formula: x = 2/3 and x = 5/7
What are the solutions of x2 minus 21x equals 72?
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
What does x2-5x equals 0?
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
Does every quadratic equation have two distinct real numbers in its solution set?
Nope. Consider x2+0x+1=0. This means x2+1=0. This has two solutions, but they are complex numbers: +i and -i, where i is the squareroot of -1. How about x2+0x+0=0? This means x2=0. This has two solutions, sure, but they aren't distinct. In this case, x=0 for both solutions, so we just consider them one solution.
