Area = 12 x 10 = 120 Sq feet
Given: Length of the rectangle is 10 feet and the width is 12 feet.
Therefore, the area of the rectangle = (10*12)
The area of the rectangle is 120 square feet.
12*10 = 120 square feet
The perimeter of a rectangle 12 inches by 8 inches is 40 inches. Its area is 2/3 of a square foot.
it is a wong question . it is because for finding the perimeter we need both length and width.
1 square foot.
24
22
12
Multiply width by length to get the area. The answer would be 112 square feet.
The area of rectangle is : 44.0
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
You must convert each measurement (length and width) from whatever unit of measurement you have used into feet; then multiply the length (in feet) times the width (in feet). The result will be the area in square feet.
The area of the room is not enough information to determine its width. Based on the normal usage, which implies that the width is less than the length, the only assertion possible is that the width is at most sqrt(185) ft , that is, at most 13.6 feet.
The area of a rectangle is length x width.
The area of the rectangle is 72 square feet
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
The length is 7 feet and the width is 5 feet
The width is 6 feet. The length is 8 feet.
area = length x width width = area/length 16/8 = 2 feet
The area of rectangle is : 120.0
Area of a rectangle = length * width = 72 feet-squared
Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet
The width is 16 feet
width=16 and length=20