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Q: How many square feet would 41 tiles 16 x16 inches cover?

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You will need at least 66,828 1/4 tiles to cover that area.

If your tiles are 12 inches x 12 inches you would need 144 of them.

Assuming you mean 16x16 inches tiles... 441 tiles would cover the area exactly

If they 16 is in inches, this would be 256 square inches per tile. That would cover 10,496 square inches. Divide by 144 and you get 72.89 square feet.

11 feet x 14 feet = 154 square feet. You would need 9 tiles, that measured 4 inches x four inches, to cover one square foot. So you would need 154 x 9 tiles to cover the entire area, which is 1386 tiles.

You would need 137 (136.23) 16" x 16" tiles to cover 22.5 square meters.

776. You need four tiles for one square foot (tiles are 36 square inches, a square foot is 144 square inches) so 4 tiles times 194 sqft is 776. You will want some spares too.

12 inches = 1 foot Thus the tiles would be 1 foot square. You therefore need 30 to cover a 30 square foot room.

Assuming you mean 18 inch tiles... 290 square feet is 41,760 square inches. Each tile is 324 square inches - so you would need 129 tiles in total (with a fraction of a tile left over)

49 tiles

Tiles that are two feet on a side cover 4 square feet. 378 of them cover 1512 square feet.

To cover 345 square feet with 16x16 tiles , you need at least 195 tiles (194 and 1/16 exactly). 345 square feet x 144 square inches/sq ft = 49680 square inches 16 x 16 = 256 square inches per tile 49680 / 256 = 194.0625 It could take more because you may have to use large fractional tiles on edges, and some may break.

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