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How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
how many squares with sides that are 6 inches long are needed to cover a squae with a side length of 30 inches without overlapping
8 squares. One of 11x11 Five of 2x2 Two of 1x1
10,000 of them.
Eight squares are needed.
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
how many squares with sides that are 6 inches long are needed to cover a squae with a side length of 30 inches without overlapping
8 squares. One of 11x11 Five of 2x2 Two of 1x1
It should be obvious that the answer depends on how large the bigger square is.
10,000 of them.
Eight squares are needed.
The answer depends on the size of the squares.
Eight, which will be sufficient for 14 squares.
6 sides are needed
Assuming that the floor squares are 11" x 11" and the dance floor is 9ft x 20ft, we can proceed as follows. 9ft = 108 inches and 20 ft = 240 inches. The product of the two which is the ares of the dance floor is 25920 square inches. Divide this by (11 x 11 = 121) to get 25920/121 = 214.214 squares. Since each package has 10 squares you would need 21.4214 packages. Since the shop keeper will not sell you fraction of a package plan on getting 22 packages.
The units may be any squared units. It is an area. They may be square inches, feet, yards, miles, metres, kilometres etc.
2 squares and 4 rectangles * * * * * 6 rectagles in three pairs. The ends need not be squares.