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8(6741)3= 8(7654)3 the digits between 8,3 are 4.

6(7)4=6(5)4

so the answer is four (8,3&6,4)

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Q: How many such digits are there in the number 58674139 each of which is as far away from the beginning of the number as when the digits within the number are rearranged in descending order?
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