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Q: What is the mean mode and median to 82 79 93 91 95 95 81?

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The mean is: 81.6 The median is: 81 Its mode is: 81 and 83 because its bi-modal

The median and mode are both 82. The mean is 84.6

median is 79. Write in order; median is middle number: {72, 89, 67, 81, 75, 79, 81, 80, 62, 64, 83} → {62, 64, 67, 72, 75, 79, 80, 81, 81, 83, 89} To find middle number, count the number of data items, add 1 and divide by 2. If this is a whole number, that is the data item which is the median; if it is a fraction, take the mean average of the data items of the positions either side of the fraction (eg if the fraction is 3.5, take the mean average of the 3rd and 4th data items) There are 11 data items → median is (11+1)/2 = 6th data item → median is 79

Mean: 69 Median: 67 Mode: 83, 61

meanAdd up the numbers and divide by how many there are: 87+75+89+81+90+73+85+96+65+92+78+79+83+85+79+90+86+72+74+88+81+85 = 1813There are 22 numbers.â‡’ mean = 1813 Ã· 22= 829/22â‰ˆ 82.41medianSort the numbers into order; the median is the middle number (if an odd number of numbers) or the mean of the middle two (if an even number of numbers): Sorted: 65, 72, 73, 74, 75, 78, 79, 79, 81, 81, 83, 85, 85, 85, 86, 87, 88, 89, 90, 90, 92, 96There are 22, so the median is the mean of the middle two which are the 11th (83) and 12th (85) numbers:â‡’ median = (83+85) Ã·2= 84modeThe number which appears the most often. Having sorted the list for the median, it can be seen that the one with the highest frequency appears three times: â‡’ mode = 85

Assuming you mean the arithmetic mean, it is 80.

the mean is 79.75

For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62

83

There is no mode because no number appears more than once.

It is 80.5, the number halfway between them. Median means "half of the numbers are above and half are below". With only two numbers we just split the difference. In this case the Median and the Mean are the same number - but this is not always the case. If our numbers were 80, 80, 81, 83, the Median would still be 80.5 but the Mean would be 81.

81

79-81 AD was the 1st century AD.

78 + 79 + 80 + 80 + 81 + 81 = 479

81.

The mean average is 51

85

It is 81

79

I'm going to guess that's the set (5, 5, 6, 7, 8, 8, 10, 10, 10, 12) Sum: 81 Mean: 8.1 Mode: 10 Range: 7

72 73 79 75 76 81 81 85 88

It depends on what average you want to find. To find the mean of 81, 81, 98, and 91 add the numbers together and divide by 4 (the number of numbers you added). 81 + 81 + 98 + 91 = 351 351 divided by 4 = 87.75. To find the median, list the numbers in order and find the one in the middle. 81, 81, 91, 98 81 and 91 are in the middle. To find the mode, look for the number that appears the most, 81 appears twice and the other numbers appear once. 81 is the mode.

It is the middle value which is 81

They are: 79+2 = 81

For median the list needs to be sorted into increasing order, but doing so also helps with the range and mode, so I'll do that first: {89, 76, 85, 76, 77, 84} → {76, 76, 77, 84, 85, 89} Mean: add them up and divide the sum by how many numbers there are: mean = (89 + 76 + 85 + 76 + 77 + 84) / 6 = 81 1/6 ≈ 81.167 Median: middle number when listed in order; if there are an even number of data items, then the median is the mean average of the middle two: There are 6 data items so median is mean average of middle two: median = (77 + 84) / 2 = 80 ½ = 80.5 Mode: the most frequent, it the number which occurs the most often. There can be more than one mode: mode = 76 as there are two of them and only 1 of all the other numbers. Range: the difference between the greatest and least numbers: range = 89 - 76 = 13