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Q: How long is the diagonal of a rectangle with the length of 30 yd and the width of 30 yd?

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infinitely far

If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.

Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764

15 cm Solved through Pythagoras' theorem.

-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)

A rectangle is a four-sided figure with two long sides and two short sides. The two long sides are the length of the rectangle. The two short sides are the width of the rectangle.

15 cm for the diagonal.

If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

The area of a rectangle is simply the length times the width. If the length and width are in meters, the area, of course, will be in square meters.

To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m

The width and the length are independent. You can have a very long rectangle which is very wide or not wide at all. They are related when it comes to calculating area or perimeter of the rectangle. Perhaps that is what you meant?

The area of a rectangle is length x width. So the length, which is 9, times the width, which equals five, equals 45 metres.

Using Pythagoras' theorem it is 26 inches in length

Other than what? It really all depends on what is given. For example:If you know the length of one diagonal, the other is just as long.If you know the length and width of the rectangle, use Pythagoras' formula for the diagonal.If you know one of the sides of the rectangle, and an angle, use some basic trigonometry to find the diagonal.

yo brotha!

That depends how wide it is; it is not possible to calculate the area without a width. (As you say "rectangle" I'm assuming the width is different to the length).

Area of rectangle = length * width = 9*8 = 72 metres2

You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com

The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)

You CAN'T calculate the surface area of a rectangle, given only its perimeter. The answer varies, depending on the length-to-width ratio of the rectangle. Thus, you would need some additional information; for example one of the following:* The length * The width * The length-to-width ratio * The length of the diagonal * Some other data that will let you calculate the remaining information about the rectangle.

Approximately 15.62 feet.

15 inches (solved with the help of Pythagoras' theorem)

Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft

If the area is of a rectangle, it is simply the length times the width. If you have a rectangle with sides of 2 and 50 then the area is 100.

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