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Q: What is the nth term of the sequence 3 10 17 24?

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The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.

Just subtract 9.

It is: nth term = 35-9n

The nth term is 7n-4 and so the next number in the sequence is 31

The nth term is 5n-3 and so the next term will be 22

The nth term is 25-4n and so the next term will be 5

5

I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7

The nth term is: 3n+2 and so the next number will be 20

You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4

tn=5n-3

7(n2-1) - 4

The sequence progresses by adding 7 to the previous term.The nth term is thus equal to 10 + 7n. The 11th term therefore is equal to 10 + (7 * 11) = 10 + 77 = 87.

It is: 27-2n

5, 11, 17, 23, 29

n+4

The nth term is 2n+5 and so the next number is 17

9, 17, 25, 33, 41

One possible answer is t(n) = (n5 - 10n4 + 55n3 - 110n2 +364n)/60

t(n) = 12*n + 5

t(n) = 28 - 9n

5, 8, 11, 14 and 17.

7n+4

you can find the rest of the numbers in the sequence by using inductive reasoning or noticing a pattern 26 , 17 , 8 , -1 , -10 it appears that you are subracting 9 each time. 26-9=17 17-9=8 8-9=-1 (8-9 changes to 8+-9 if you need to see that step) -1-9=-10 (-1-10 changes to -1+-9 if you need to see that)

5 to 7 is 27 to 17 is 1017 to 19 is 219 to 29 is 1029 to 31 is 2there fore following the pattern the nth term is 4131 to 41 is 10

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