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How many vertices does a septagon have?

Updated: 4/28/2022
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A septagon or an heptagon has 7 vertices and 7 sides

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Seven.

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Q: How many vertices does a septagon have?
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Related questions

How many vertices dose a septagon have?

It has 7 vertices


How many diagonals in a septagon?

Not sure about a septagon, but there are 14 diagonals in a heptagon.


How many 35 sides a septagon/heptagon?

The answer is 35


What is another name for a septagon?

another name for a septagon is a heptagon


What is a seven sided polygon is called a?

a heptagon


A shape that has seven sides?

septagon septagon * * * * * Actually, it is called a heptagon.


How many diagonals does a septagon have?

There are 14 diagonals in a septagon. Another name for a septagon is heptagon. This is a seven-sided polygon. To figure the numbers of diagonals, you can use the formula 1/2 x [n x (n-3)], where n is the number of sides.


How many sides does a septagon has?

It has 7 sides and it is also known as a heptagon


Is a septagon a parallelogram?

No because a septagon is the same as a heptagon which is a 7 sided polygon


How many diagonals in 50-gon?

for any polygon with 'n' number of sides, the number of diagonals will be n(n-3) / 2 if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175 how do you get it? take any polygon, say septagon i.e. with 7 sides if you take 1 vertice, remainig vertices will be 7-1 that is 6. there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4. remember : a diagonal connects non consecutive vertices so you know that from one vertice, there will be 4 diagonals. multiply it by the total no. of vertices(here 7) 4*7 = 28 now divide this by 2 (since 2 vertices share the same diagonal) therefore, 28/2 = 14 which is the no. of diagonals in a septagon. so for an n-gon, the number of diagonals will be n(n-3) / 2 hope it helps! p.s. i figured it out myself during math class. then i tried it on many polygons.


How many diagonals in a 50-gon?

for any polygon with 'n' number of sides, the number of diagonals will be n(n-3) / 2 if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175 how do you get it? take any polygon, say septagon i.e. with 7 sides if you take 1 vertice, remainig vertices will be 7-1 that is 6. there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4. remember : a diagonal connects non consecutive vertices so you know that from one vertice, there will be 4 diagonals. multiply it by the total no. of vertices(here 7) 4*7 = 28 now divide this by 2 (since 2 vertices share the same diagonal) therefore, 28/2 = 14 which is the no. of diagonals in a septagon. so for an n-gon, the number of diagonals will be n(n-3) / 2 hope it helps! p.s. i figured it out myself during math class. then i tried it on many polygons.


What is a 7-sided shape called?

Heptagon/Septagon it can be either