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Richard Grimes

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3y ago
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Wiki User

13y ago
AnswerAssuming that each person in the group has the same likelihood of being chosen:

The answer is (6!/3!)/3!. This is the quotient six factorial divided by three factorial, divided by 6. It comes to 20.

You divide by six because the different orders of selection do not create unique committees. Choosing Jane, Paul and Alex, for example, gives you the same committee as if you had chosen Jane, Alex and Paul, or Paul Jane and Alex. There are six ways that three individuals can be ordered (3!).

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Wiki User

11y ago

Using Numbers as identifiers: 34

12345

12346

12347

12348

12349

12356

12357

12358

12359

12367

12368

12369

12378

12379

12389

23456

23457

23458

23459

23467

23468

23469

23478

23479

23489

34567

34568

34569

34578

34579

45678

45679

45689

56789

* * * * *

That is incorrect.

There are, in fact, 9C5 = 9*8*7*6/(4*3*2*1) = 126 ways.

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Q: In how many ways can a 3-person committee be selected from a group of 6?
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