One hundred thousand. Since the first set of three digits has been assigned 10 possible permutations, then just let a digit 0 through 9 (ten possibilities) represent that set, then you have the other four digits, so you have a five digit permutation, {0-9} in each position. So we have from 00000 to 99999, which is 100,000 possibilities. Or if you want to think of it a different way, each three digit exchange can have ten thousand numbers 0000 to 9999. There are 10 exchanges, so multiply 10,000 by 10 = 100,000.
None of them. The digits, arranged in descending order, are: 97654321 9 is 1 digit from the start 7 is 2 digit from the start etc So none.
The number 8549176320 has all the digits arranged in alphabetical order.
As a string, the largest number is 7111111.
The first digit would have to be 1, the remaining digits, zero.
The number is: 36725918 In descending order that is: 98765321 The pairs of numbers that have as many digits between them in both are: 3,9 5,8 6,7 So there are three pairs.
It's the only number where the digits are arrange alphabetically, eight...five...four...nine...one...seven...six...three...two...zero. Actually, that answer is not completely true as stated. If you were to plug this number into Google you would find this same answer all over the web. It doesn't take a genius to realize that it is NOT the ONLY number where the digits are arranged alphabetically. For example, drop the 0 at the end and you STILL have a number that is arranged in alphabetical order. The answer should probably say, "It's the only number using all digits between zero and 9, that is arranged in alphabetical order".
The 7 can go in any of seven places and the 4 in any of the remaining 6. It is irrelevant which 2 goes where so there are 7 x 6 ie 42 possibilities which result in distinct sequences.
Multiply the last digit by 7. Subtract that number from the remaining digits. If that number is divisible by 23, then the original number is divisible by 23.
99
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
The US uses ten digits in their number format. For example - the number would look like 800-123-1234. In that example, 800 is the area code, and the remaining 7 digits are the subscribers number.
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.