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Q: How many ways can first place second place and third place winners be selected from four finalists?
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If there are 6 contestants in a race the number of different ways the first and second place winners is?

6 X 5 = 30: There are 6 possible winners, and with the winner chosen, there remain 5 possible second place finishers. The choices are independent, so that the number of possible choices is the product of the two individual place choices.


How many ways can 4 finalists be selected from 50 people?

You have 50 ways to select the first.For each of those 50, you have 49 ways to select the second.Only 49 ways, because for each of the 50, there are only 49 left to select from.That's 50 x 49 ways to select the first and the second.For each of those 50 x 49 ways, you have 48 ways to select the third.That's 50 x 49 x 48 ways to select the first, second and third.For each of those 50 x 49 x 48 ways, you have 47 ways to select the fourth.That's 50 x 49 x 48 x 47 ways to select the first, second and third and fourth.But if it doesn't matter what order they are selected in, the same four people have been counted multiple times. For example, if people A, B, C and D have been selected, we will have counted A, B, C and D as one way, and D, C, B and A as another, B, D, A and D as another. In fact, there are 4 x 3 x 2 x 1 ways of counting any four people.So if order does not matter, there are (50 x 49 x 48 x 47) / (4 x 3 x 2 x 1) ways.How many ways can 5 finalists be selected from 100 people?


What is 1 7583837563728283727847372784829390493848728378183783748375564752748829?

Two numbers: the first of them is 1 and the second is not!Two numbers: the first of them is 1 and the second is not!Two numbers: the first of them is 1 and the second is not!Two numbers: the first of them is 1 and the second is not!


A sample of 4 iPods is selected from a shipment of 20 iPods there are 5 defective iPods in the shipment what is the probablity that the sample does not contain any defective iPods?

i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%


Is the word remind a first syllable or second syllable accented?

first

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When are cells selected in Excel?

You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.You can interpret that question in two ways. In the first sense, cells are selected when you want to do something with them, like copy them or format them. In the second sense, cells are selected when they are highlighted. This can be done with the mouse or keyboard.


Who were the losing semi-finalists of the 2002 world cup?

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Was tokyo a finalists for the 2016 olympic games?

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If 50 people are chosen at random what is the probability that at least two of them have their birthday on the same day?

There being 365 days in a year and 50 being less than 365 therefore 2 even far less than that the chances are virtually 0. ______________________ Assume that all 366 days (including leap day) are equally likely to be a person's birthday. The probability that none of them share a birthday is 1*P(second person selected doesn't share a birthday with first person selected)*P(third person selected doesn't share a birthday with first or second person selected)*...*P(fiftieth person selected doesn't share a birthday with the first, second, third,...,forty-ninth person selected). P(second person selected doesn't share a birthday with first person selected) = 365/366 P(third person selected doesn't share a birthday with first or second person selected)=364/366 . . . P(fiftieth person selected doesn't share a birthday with the first, second, third,...,forty-ninth person selected)=317/366 P(none share a birthday)=(365/366)*(364/366)*...*(317/366), which is approximately .0299. P(at least two share a birthday) = 1-(365/366)*(364/366)*...*(317/366)=1-.0299=.9701 = 97.01%.


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