answersLogoWhite

0


Best Answer

The number of permutations of the letters in PREALGEBRA is the same as the number of permutations of 10 things taken 10 at a time, which is 3,628,800. However, since the letters R, E, and A, are repeated, R=2, E=2, A=2, you must divide that by 2, and 2, and 2 (for a product of 8) to determine the number of distinctpermutations, which is 453,600.

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many ways can the letters in prealgebra can arranged?
Write your answer...
Submit
Still have questions?
magnify glass
imp