5.
This question is the same as asking how many factors does 18 have.
18 has the following factors:
1, 18, 2, 9, 3 & 6.
Therefore you could pile the books 6 different ways.
However, as the question says equal piles (plural) then I think we should probably discount 1 pile of 18 books, so the answer is 5.
I would say 77 because if there are 77 books, you could put each different book in a different place 77 times.
Add all the books and divide by 4: 18 + 19 + 24 + 23 = 84; 84 divided by 4 = 21 books per stack
Only one stack - if it is big enough.
Let x = third pile First Pile = 2x + 10 Second Pile = 2x Third Pile = x (2x+10) + (2x) + (x) = 3000 2x + x + 2x + 10 = 3000 5x + 10 = 3000 5x = 3000 - 10 5x = 2990 x = 2990/5 x = 598 Therefore there are 598 books in the third pile. I'm sure you can figure out how to get how many books are in all other piles.
20 dimes
i think about 5929 ways
I would say 77 because if there are 77 books, you could put each different book in a different place 77 times.
5 ways the factors of 52 are 13, 2, and 2 a deck can be divided into 52 piles of 1, 26 piles of 2, 13 piles of 4, 4 piles of 13, and 2 piles of 26
3 ways
Assuming each coin is 1 cent. Two piles of 15 coins each (15 + 15 = 30).
43 stacks and one third of a stack.
Add all the books and divide by 4: 18 + 19 + 24 + 23 = 84; 84 divided by 4 = 21 books per stack
3000
yes there are many photos if you look on google images, books and history websites.
Use the factors of the number. Factors of 10 are... 1,2,5 & 10. Therefore they will stack either in 1 row of 10 books or 2 rows of 5.
1
¿Cuántos libros son?How many books are there?Literally asking "How many books are?" The qualifier depends on who is asking whom the question where. You are holding a stack of books and some one asks this question, they are asking how many books you have. You are standing in a library and some one asks you that question while gesturing to the library, they are asking how many books are in the library.