In order to be divisible by both 2 and 3, a number must be divisible by 6.
The largest multiple of 6 less than 100 is 96 ... the 16th multiple of 6.
So there are 16 of them.
If you mean how many can be divided by both 2 and 3, then it would be the multiples of 6 between 1 and 100: This would be numbers of the form 6k, where k is a whole number. There are 16 values of k for which 1<=6k<=100 [I don't think I can make a proper less than or equal sign on here, so I am using "<="]. k=1,2,3,4,...,16, with 6k=6,12,18,...96 If you mean how many are divisible by either 2 or 3 (or both), this would be the number of whole numbers divisible by 2+the number of whole numbers divisible by 2-the number of whole numbers divisible by 6 [to eliminate double counting]. By the same rationale applied above for 6, there are 50 numbers between 1 and 100 inclusive that can be divided by 2, and 33 numbers that can be divided by 3. So there are are 50+33-15=73 that can be divided by either 2 or 3 (or both).
Only 66.
The are six such numbers: 18,36,54,72, 90 and 108 .
6 12 18
both are multiples of 4, 2, and 8 because they're divisible by 2, they're even numbers Both are positive integers (whole numbers greater than 0)
There are 75 whole numbers from 100 to 999 that are divisible by both three and four.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.
If you mean how many can be divided by both 2 and 3, then it would be the multiples of 6 between 1 and 100: This would be numbers of the form 6k, where k is a whole number. There are 16 values of k for which 1<=6k<=100 [I don't think I can make a proper less than or equal sign on here, so I am using "<="]. k=1,2,3,4,...,16, with 6k=6,12,18,...96 If you mean how many are divisible by either 2 or 3 (or both), this would be the number of whole numbers divisible by 2+the number of whole numbers divisible by 2-the number of whole numbers divisible by 6 [to eliminate double counting]. By the same rationale applied above for 6, there are 50 numbers between 1 and 100 inclusive that can be divided by 2, and 33 numbers that can be divided by 3. So there are are 50+33-15=73 that can be divided by either 2 or 3 (or both).
12
33 divisible by 3. 14 divisible by 7. 4 divisible by both. Total: 43
670
Only 66.
Four. 24 and its multiples.
Two numbers: 126 and 147
The are six such numbers: 18,36,54,72, 90 and 108 .