t = number of liters of 30% acid solution
s = number of liters of 60% acid solution
t+s=57
.30t+.60s=.50*57
t=57-s
.30(57-s)+.60s=.50*57
.30*57 -.30s +.60s = .50*57
.30s = .50*57 - .30*57 = .20*57
s = .20*57/.30 = 38 liters of 30% solution
t = 57 - s = 57-38 = 19 liters of 60% solution
by mixing 6.67 gallons of 20 solution & 3.33 gallons of 30 solution will give 10.00 gallons of 30 solution.
8 gallons of 20 percent and
4 gallons of 50 percent
Each should be 70
The answer is 31,05 g ethanol.
If you're talking about 10 liters of water and not percent, then 10 liters. But then you'll have 60 liters of mixture. It would be 2/5 or 0.4 x 50 = 20 this would make a mix of 20/50. Waterman
222.223 ml @ 20% solution = 44.444 ml 277.777 ml @ 65% solution = 180.555 ml total = 225 ml out of 500 ml = 45%
80% water
10 liters.
Add 0,8 L of water.
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
6 litres of 50% + 4 litres of 25%
add 25ml more of solution x * 20 = 100 * 25 x = 25
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
2%
600ml.
3 to 4 liters of water
This is an algebra problem. There will be 2 equations and 2 unknowns. Let x = amount of 7% solution, and y = amount of 19% solution. .07x + .19y = .15*456. x + y = 456; or x = 456-y which will substitute into the first equation. .07(456-y) +.19y = .15*456. 31.92-.07y+.19y = 68.4. .12y = 36.48. y = 304L (amount of 19% solution to add). x = 456-y. x = 456 - 304. x = 152L (amount of 7% solution to add).