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do you mean 100 ml? most solutions are given in terms of volume not mass. But ...

CaCl2 has a molar mass of 111 g The hydrated form also contains 108 g water. This gives a total mass of 219 g for the hydrated form.

The solution must contain: 100 g x 5% = 100 x 5/100 = 5g anhydrous CaCl2

5 / x = 111 / 219

solve for x: x = 5(219)/111 = 9.865 g of the hydrate

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Q: How much CaCl2.6H2O and water must be weighed to prepare 100g of a solution that is 5 percent CaCl2?
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