for every 5 moles of y there is 1 mole of x, so 3.8/5 is .76
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The balanced chemical equation shows that 1 mole of oxygen reacts with 2 moles of hydrogen to form water. Therefore, if you have 1.42 moles of hydrogen, you would need 0.71 moles of oxygen to react with it in this reaction.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
Yes, the number of moles will remain the same as long as the chemical does not react with water.
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The balanced chemical equation shows that 1 mole of oxygen reacts with 2 moles of hydrogen to form water. Therefore, if you have 1.42 moles of hydrogen, you would need 0.71 moles of oxygen to react with it in this reaction.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
To determine the number of moles of oxygen needed to react with 4.52 moles of carbon monoxide (CO), we refer to the balanced chemical equation for the reaction: 2 CO + O₂ → 2 CO₂. From the equation, 2 moles of CO react with 1 mole of O₂. Therefore, to find the moles of O₂ required, we can use the ratio: (4.52 moles CO) × (1 mole O₂ / 2 moles CO) = 2.26 moles of O₂. Thus, 2.26 moles of oxygen are needed to react with 4.52 moles of CO.