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How much X will remain in 4.0 moles of X and 3.8 moles of Y are allowed to react. X plus 5Y equals 3Z?
To determine the limiting reactant and thus how much X remains, first calculate the moles of Z produced using the mole ratio from the balanced equation, given moles of X and Y. Then, identify the limiting reactant by comparing the moles of Z produced from each reactant. Finally, determine the moles of X remaining by subtracting the moles of Z produced from the moles of X initially given.
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How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
H2 plus O2 equals H2O If you have 1.42 moles of hydrogen how many moles of oxygen will react with it?
The balanced chemical equation shows that 1 mole of oxygen reacts with 2 moles of hydrogen to form water. Therefore, if you have 1.42 moles of hydrogen, you would need 0.71 moles of oxygen to react with it in this reaction.
How many moles of Cu(NO3)2 are produced when 3 moles Cu react?
When 3 moles Cu react 3 moles of copper nitrate are obtained.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
Is the number of mole remain same if you add distilled water?
Yes, the number of moles will remain the same as long as the chemical does not react with water.
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
H2 plus O2 equals H2O If you have 1.42 moles of hydrogen how many moles of oxygen will react with it?
The balanced chemical equation shows that 1 mole of oxygen reacts with 2 moles of hydrogen to form water. Therefore, if you have 1.42 moles of hydrogen, you would need 0.71 moles of oxygen to react with it in this reaction.
How many moles of Cu(NO3)2 are produced when 3 moles Cu react?
When 3 moles Cu react 3 moles of copper nitrate are obtained.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?
When 4 moles of aluminum react with an excess of chlorine gas (Cl2), 4 moles of aluminum chloride are produced because the balanced chemical equation for this reaction is: 2 Al + 3 Cl2 -> 2 AlCl3 Since the mole ratio between aluminum and aluminum chloride is 2:2, it means that for every 2 moles of aluminum, 2 moles of aluminum chloride are produced.
How do you find the number of moles that will react with 5 grams of butane?
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
How many moles of sodium oxide will react with 42.0 moles of water?
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
How many gram of f2 are required to react with 3.50 moles of nh3?
The balanced chemical equation for the reaction between F2 and NH3 is: 3 F2 + 4 NH3 -> 6 HF + N2 From the equation, we can see that 3 moles of F2 react with 4 moles of NH3. To find the moles of F2 required to react with 3.50 moles of NH3, we can set up a proportion: 3 moles F2 / 4 moles NH3 = x moles F2 / 3.50 moles NH3 Solving for x, we find that 2.625 moles of F2 are required. To convert this to grams, we use the molar mass of F2 which is approximately 38.00 g/mol. 2.625 moles F2 x 38.00 g/mol = 99.75 grams of F2 required to react with 3.50 moles of NH3.
