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How much energy was transferred to the water of 1.3 kg of water equals from 20 degrees to 100 degrees c?
Wiki User
∙ 12y ago
1.3 kg water = 1300 grams.
q(Joules-heat energy) = mass * specific heat * change in temperature
q = (1300 g)(4.180 J/gC)(100 C - 20 C)
= 4.3 X 105 Joules of heat energy
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Wiki User
∙ 12y ago
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