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Q: How many possible 5 digit combinations with 20 no?

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There are 1140 five digit combinations between numbers 1 and 20.

There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.

There are 38760 combinations.

There are 167960 9 digits combinations between numbers 1 and 20.

There are 167960 9 digits combinations between the numbers 1 and 20.

There are 167960 combinations.

I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.

Statistically, the number of different tripeptide combinations possible of the 20 amino acids is 8000 (20*20*20).

20*20 = 400

116,280

20

The human body produces about 100,000 different types of proteins.

Assuming you are using combinations in the colloquial way (which is the mathematical "permutations" where order of selection does matter) to create a 3 digit number that does not start with 0, ie creating a number that is between 100 and 999 inclusive then: If repeats are not allowed there are 3 × 3 × 2 = 18 possible numbers If repeats are allowed, then there are 3 × 4 × 4 = 48 possible numbers. If you are using combinations in the mathematical sense where order of selection does not matter and are creating groups of 3 digits, then: If repeats are not allowed there are 4 possible groups If repeats are allowed there are 20 possible groups.

The number of combinations are 10*20*30; which is 6000.

86,450

There are 4845 combinations.

Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216

20*19*18*17*16/(5*4*3*2*1) = 15504

There are 6C3 = 20 such combinations.

There are many different combinations of amino acids and proteins and peptide bonds.

20

There are 125970 combinations and I am not stupid enough to try and list them!

If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.

20 and 30, among other possible combinations.

It is not possible to answer the question without information on the units used for 7 x 20. Are they inches, feet, miles, light years or combinations of these eg 7 inch * 20 light years.