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200%.

Careful here! An 800% increase is equivalent to multiplying by 9 - NOT 8. So the sides need to be multiplied by sqrt(9) = 3. That is an increase of 200%

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Q: How much percent of the side should be increased so that the area of the square should increase 800 percent?

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10

Each side will increase by the square root of 69 (approx. 8.3).

That would depend on the original side lengths of the square which have not been given.

Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.

66

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By 44%. Here is how you calculate it: 20% increase is equivalent to an increase by a factor of 1.2 (100% + 20%, converted to decimal). Square that, and you get 1.44 (44% more than the original).

10

Kinetic energy is proportional to the square of the speed; use this fact to calculate the increase in speed (60% increase means an increase by a factor of 1.6). Momentum is proportional to the speed.

Each side will increase by the square root of 69 (approx. 8.3).

That would depend on the original side lengths of the square which have not been given.

If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.

Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.

66

56.25% let side of square is 'a' its perimeter is 4a its area is axa perimeter increase by 25% new perimeter is 5a new sideof square becomes=5a/4= 1.25a its new area is 1.25ax1.25a increase in area in percentage is ((1.25ax1.25a)-(axa))/(axa) *100 =56.25%

I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.

The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.