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How much percent of the side should be increased so that the area of the square should increase 800 percent?
Wiki User
∙ 12y ago
200%.
Careful here! An 800% increase is equivalent to multiplying by 9 - NOT 8. So the sides need to be multiplied by sqrt(9) = 3. That is an increase of 200%
Wiki User
∙ 12y ago
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If the length of each side of the square is increased by 10 percent by what percent does the area of the square increased?
10
If the area is increased by 69 then how much the side of the square will increase?
Each side will increase by the square root of 69 (approx. 8.3).
By what percent does the area of a square increase if its side increases by 10?
That would depend on the original side lengths of the square which have not been given.
How many times is the period of the pendulum increased or decreased when its length is increased four times?
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.
How many square centimeters does the area increase if the length and width of a rectangle with a perimeter of 62 are each increased by 2 centimeters how do you solve this?
66
If the area of the square is increased by 69 percent how much the length of the side will increase?
30%
If the sides of a square are increased by twenty percent by what percent does the area of the square increase?
By 44%. Here is how you calculate it: 20% increase is equivalent to an increase by a factor of 1.2 (100% + 20%, converted to decimal). Square that, and you get 1.44 (44% more than the original).
If the length of each side of the square is increased by 10 percent by what percent does the area of the square increased?
10
If kinetic energy is increased by 60 percent then momentum will be?
Kinetic energy is proportional to the square of the speed; use this fact to calculate the increase in speed (60% increase means an increase by a factor of 1.6). Momentum is proportional to the speed.
If the area is increased by 69 then how much the side of the square will increase?
Each side will increase by the square root of 69 (approx. 8.3).
By what percent does the area of a square increase if its side increases by 10?
That would depend on the original side lengths of the square which have not been given.
If the side of a square is doubled in size to 8 by what percent did its area increase?
If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.
How many times is the period of the pendulum increased or decreased when its length is increased four times?
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.
How many square centimeters does the area increase if the length and width of a rectangle with a perimeter of 62 are each increased by 2 centimeters how do you solve this?
66
How do you solve if perimeter of a square increases by 25 percent then its area increases by how much percent?
56.25% let side of square is 'a' its perimeter is 4a its area is axa perimeter increase by 25% new perimeter is 5a new sideof square becomes=5a/4= 1.25a its new area is 1.25ax1.25a increase in area in percentage is ((1.25ax1.25a)-(axa))/(axa) *100 =56.25%
Is the length of a side of a square and its area nonlinear?
I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.
If the surface area of a sphere is increased by a factor of 4 what is the change in the length of the radius of the sphere?
The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
