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Q: How much power is required in watts for a 90 kg woman to climb a ladder 6 meters in height in 3 seconds?

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5 meters

Work = (force) x (distance) = m g H = (90) x (9.807) x (6) = 5,295.78 joulesPower = work/time = 5,295.78/3 = 1,765.26 watts = 2.366 horsepowerA physically impossible feat, but the math is bullet-proof.

approx. 50 seconds

19.6 meters / 64.4 ft

Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters

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cos60=4.2cm/x x=4.2cm/cos60 x=8.4cm Therefore the height of the ladder is 8.4cm. However, i think you mean meters because that is a very tiny ladder lol.

15 meters, or less, depending on the angle.

At least 3,500 joules, if his climbing effort is 100% efficient, but probably more than that.

5 meters

5 meters

Work = (force) x (distance) = m g H = (90) x (9.807) x (6) = 5,295.78 joulesPower = work/time = 5,295.78/3 = 1,765.26 watts = 2.366 horsepowerA physically impossible feat, but the math is bullet-proof.

approx. 50 seconds

6.71 meters.

19.6 meters / 64.4 ft

The time required for a stone to fall from a given height can be calculated mathematically. Time equals the square root of two times the distance divided by force of gravity. Time is in seconds, distance in meters, and the force of gravity on Earth is 9.8 meters/second ^2.

Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters

Height (feet): 25550; Height (meters): 7788