47.7 cubic feet
How much cement is needed to cover 192 square feet of area
120
You'll need about 28.704 cubic yards (37 tons) of gravel.
You will need about 463 cubic yards (around 594 tons) of gravel for this area.
First you need to tell us what the units of your 8x4 blocks are. For example, feet, or inches.
Approximately 5.8 square feet. Six square feet to be safe.
You will need about 3.7 cubic yards (around 4.75 tons) of gravel.
You will need 1500 cubic feet.
To calculate the amount of soil needed, you multiply the area by the desired depth. In this case, you have 9300 square feet and want a depth of 12 inches. Convert the depth to feet (12 inches = 1 foot) and multiply: 9300 square feet x 1 foot = 9300 cubic feet of soil. So, you need 9300 cubic feet of soil to cover the area with a depth of 12 inches.
25 cubic feet or about 1 cubic yard.
11 feet x 14 feet = 154 square feet. You would need 9 tiles, that measured 4 inches x four inches, to cover one square foot. So you would need 154 x 9 tiles to cover the entire area, which is 1386 tiles.
How much cement is needed to cover 192 square feet of area
66 cu ft
You will need 234 square feet of turf to cover that area.
120
You'll need about 28.704 cubic yards (37 tons) of gravel.
You will need about 463 cubic yards (around 594 tons) of gravel for this area.