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When the bike is moving at 2 m/s, its kinetic energy is (1/2 m v2) = (5 x 4) = 20 joules.

When it's moving at 3 m/s, its kinetic energy is (1/2 m v2) = (5 x 9) = 45 joules.

The difference between initial KE and final KE is (45 - 20) = 25 joules.

That's how much work you have to do on it in order to increase its KE.

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Q: How much work must be done on a 10 kilograms bicycle to increase its speed from 2 meters per second to 3 meters pe second?
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