You must know the method and not just the answer. Think about this problem: What does 5% mean? It tells you that for every 100g (or ml) water, you must have 5g of NaOH. You have 235 ml water. Therefore you will have to use more NaOH. You can calculate this as follows:
(235/100)*5= 11.75g NaOH
Take it 5g of Noah in 100ml of beaker so get 5% Noah solution
Dissolve 500 g NaOH (as dry as possible) in 1 000 mL demineralized water.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
You need 50 g of this drug.
Take 2.409 ml of 3.05M NaOH mix c a balance of H2O to form 50ml of mixture
50 liters
122.5g
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
100 g of solution containing 50 g of NaOH.
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
Assuming the given solution is 50% w/w, we add equal amounts of water and KF so as to get the solution in desired quantity.
Dissolve 50 g of potassium carbonate in 100 mL of water at 20 0C.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
.17
You need 50 g of this drug.
Actually a 50% solution of sodium hydroxide would be made using enough water to total 100 mL of solution if using sodium hydroxide pellets or crystals. 50% of the total weight of the solution not 50% of the weight of the water used. As suggested by the first answer, the solution would be about a 33% solution. percentage solutions are weight for weight. Therefore 50% solution would be 50g of sodium hydroxide dissolved in 100g (100mL) of water.
Take 2.409 ml of 3.05M NaOH mix c a balance of H2O to form 50ml of mixture
50% purity NAOH liquid . if the density is 1.53 . so one liter hou much NAOH is here ?