Q: How to Calculate surface area of 18'x33' oval pool?

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the formula for calculating the surface area of an oval is A = Pi * a * b where a & b are the semimajor(half the long) and semiminor(half the short) axes

Where the question says "oval", we'll assume it's referring to an "ellipse".(Our main reason for doing that is the fact that we know the formula for the areaof an ellipse, so the light is better over there.)The area of an ellipse is: (pi) x (1/2 the long axis) x (1/2 the short axis)Area = (pi) x (120) x (70) = 26,389.4 square metres. (rounded)

No because the formula for finding the area of an oval, which is an ellipse, is quite different

709 square feet

"Oval" can be a variety of shapes. I suggest you use the equation for the area of an ellipse. Assume some convenient ratio of length-to-width.

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the formula for calculating the surface area of an oval is A = Pi * a * b where a & b are the semimajor(half the long) and semiminor(half the short) axes

Half of the height times half of the width time pi (3.1415926535897)

half of breath times half of length * * * * * times pi

An oval, or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi*a*b /4 where and so the area of half an oval is pi*a*b/8

Since it's an oval and not a circle, you would need the 'long' and 'short' diameters to be able to calculate area, which then with the depth, you can calculate volume.

12 x 24 oval

A = Pi * a * b where a & b are the semimajor(half the long) and semiminor(half the short) axes

It is 1/2*pi*a*b where a and b are the semi-major and semi-minor axes of the ellipse.

oval

An oval,or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi x a x b /4 where pi = 3.14 (approx)

Where the question says "oval", we'll assume it's referring to an "ellipse".(Our main reason for doing that is the fact that we know the formula for the areaof an ellipse, so the light is better over there.)The area of an ellipse is: (pi) x (1/2 the long axis) x (1/2 the short axis)Area = (pi) x (120) x (70) = 26,389.4 square metres. (rounded)

If the oval tank is standing with the water level parallel to the oval bottom then the surface area of the oval times the water depth is the volume. V = A x h Oval is an unprecise term. If you had said elliptical it would be easier knowing the major and minor axes. If the tank is lying down, or at any other angle than standing up, with the water surface NOT parallel to the oval bottom it becomes rather difficult.