The 90th term of the arithmetic sequence is 461
i dont get it
Type yourWhich choice is the explicit formula for the following geometric sequence? answer here...
An arithmetic sequence.
It is a sequence of numbers which is called an arithmetic, or linear, sequence.
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
Add all the numbers and divide that by the number of numbers.
A single number, such as 13579, does not define a sequence.
From any term after the first, subtract the preceding term.
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
You divide the head with the tail and do some dancing
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
You need to find the perimeter at the first few iterations and find out what the sequence is. It could be an arithmetic sequence or a polynomial of a higher degree: you need to find out the generating polynomial. Then substitute the iteration number in place of the variable in this polynomial.
The smallest that I can get, using only the basic operations of arithmetic, is -2310
It is often possible to find an explicit formula that gives the same answer as a given recursive formula - and vice versa. I don't think you can always find an explicit formula that gives the same answer.
tn = t1+(n-1)d -- for arithmetic tn = t1rn-1 -- for geometric
x = 1
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term. tn = t1 + (n - 1)d t30 = 1 + (30 - 1)6 = 175
You need an equation for the nth term of the sequence, or some other means of identifying the sequence. In general, they will be a+n, a+2n, a+3n and a+4n although some go for a, a+n, a+2n and a+3n.
tn = a + (n - 1)d where a is the first term and d is the difference between each term.