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Q: How to solve 8 to the power 2 5?

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8

ok 20-8-2-5 it can be 5, 20-8=12,12-2=10,10-5=5 or 20(-8)-2(-5) -160(-2) 320(-5) -1600 thank you

8

(2^5) / (2^2) = 2^(5-2) = 2^3 = 8

The answer is 40, 2^3=8 2^5=32, so 32+8=40

5 to the power of 8.

2^5 x 2^3 = 2^8 = 256

1 _ 2to the 3rd power and solve so it would be.... 1/8 as a fraction

Depends: (8/5)/5 = 8/25 8/(5/5) = 8

5/18 a to the power 6 = 0.277a to the power 6

u = 7 + 2 + (4 - 5) = 9 + (-1) = 8

5-3=2. 23=2*2*2=8. or 2*2=4 4*2=8

25*28/27 = 25+8-7 = 26 = 64

It is: 12-8+5 = 9

it's the same as 1 over the same number to a positive power. 2 to the power -3 = 1/ 2 cubed = 1/8

(5/8)-2 = (8/5)2 = 64/25 = 2.56

x y -3 4 -2 5 1 8

8-5(2+x)=2(x+1)

y/2 + 8 = 13 Subtract 8 from both sides: y/2 = 5 Multiply both sides by 5: y = 10

To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2

5

5/8/3/1 solve

8-7.2=.8.8+5=5.85.8

2^5 = 322^3 = 832 - 8 = 24

2

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