Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
40 grams of NaOH, into 1Liter water.. Solve, mix, cool..
put 20 grams NaOH in a glass beaker and mix it with 180 ml of water swirl it gently
and you get 10% sodium hydroxide solution.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
You must know the method and not just the answer. Think about this problem: What does 5% mean? It tells you that for every 100g (or ml) water, you must have 5g of NaOH. You have 235 ml water. Therefore you will have to use more NaOH. You can calculate this as follows: (235/100)*5= 11.75g NaOH
Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed
This solution contain 26,3 g NaOH.
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
no-AH
300g NaOH + 700g water
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
X/200 * 100 = 2.5 x= 5g
100 g of solution containing 50 g of NaOH.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.
You need 2,4 g NaOH (0,06 moles).