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Nowadays we would work out the equivalent of 4, 8, 14, and 49 into Roman numerals as IV, VIII, XIV and XLIX respectively.

However notwithstanding todays modern notation of Roman numerals inasmuch that there is historical evidence to suggest that back in the days of the ancient Roman Empire the equivalent of these numbers would have been calculated in either of the following formats:-

IIII+VIII = XII => 4+8 = 12

XII+XIIII = XXVI => 12+14 = 26

XXVI+XXXXVIIII = LXXV => 26+49 = 75

Alternatively using less numerals:-

IV+IIX = XII => (5-1)+(10-2) = 12

XII+IXV = XXVI => 12+(15-1) = 26

XXVI+IL = LXXV => 26+(50-1) = 75

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Q: How would you actually add together in two different ways 4 8 14 and 49 entirely in Roman numerals?
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How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?

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