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The roots will be equal
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How do you determine quadratic eqauation given the roots?
If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
Is it possible to get an infinite root of a number?
Generally, no. But one of the infinite roots of 1 is 1. Otherwise one of the roots would be nearly 1. Just a whisker smaller than 1 if it was the root of a number between 0 and 1, and just a whisker larger if the number was greater than 1. If the number was less than 0, then the roots would vary from the real to the complex numbers.
In the quadratic equation ax2 plus bx plus c 0 if b2 - 4ac?
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
What is the discrimenant?
The discriminant is the part of the quadratic formula which shows whether you will have two real roots, one real root, or no real roots. X = -b +/- sqrt(b^2-4ac)/2a just use the part under the radical as the discriminant b^2 - 4ac of the answer is; answer > 0-----then two real roots answer = 0-----then one real root answer > 0-----then no real roots
Why if the discriminant is zero is there no solution to the quadratic equation?
But there will be a solution if the discriminant is equal to zero: Real and different roots if b2-4ac > 0 Real and equal roots if b2-4ac = 0 But no real roots if b2-4ac < 0 in other words the graph wont make contact with or intercept the x axis.
What does the discriminant tell you when solving quadratic equations for the roots?
Whether the equation has 2 distinct roots, repeated roots, or complex roots. If the determinant is smaller than 0 then it has complex roots. If the determinant is 0 then it has repeated roots. If the determinant is greater than 0 then it has two distinct roots.
What is the discriminant test for factorability?
For a quadratic equation the discriminant is: b2-4ac If it's = 0 then the roots are equal If it's < 0 then there are no roots If it's > 0 then there are two different roots
How do you find the discriminant of a polynomial?
The discriminant of the quadratic equation ax2+bx+c = 0 is the value of b2-4ac When b2-4ac = 0 then there are 2 equal roots. When b2-4ac > 0 then there are 2 different roots. When b2-4ac < 0 then there are no roots at all.
How would you best describe 'Next' brand?
Differenzdruck- Messumformer 0-25 Pa bis 0-100 kPa
How do you determine quadratic eqauation given the roots?
If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
Is it possible to get an infinite root of a number?
Generally, no. But one of the infinite roots of 1 is 1. Otherwise one of the roots would be nearly 1. Just a whisker smaller than 1 if it was the root of a number between 0 and 1, and just a whisker larger if the number was greater than 1. If the number was less than 0, then the roots would vary from the real to the complex numbers.
When the discriminant is greater than 0 how many real roots are there?
There will be 2 real roots
-6 square roots of 3 plus 6 square roots of three?
It is: 0
What Are the roots of x2 plus 11x plus 30 equals 0?
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
Formula of quadratic equation if roots are given?
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
How do you describe a volcano with a vei of 0 or 8?
A volcano with a VEI of 0 would be a gentle out pouring of lava from a cone, meanwhile a 8 is a supervolcano.
