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Divide 7 into 291. If the answer is an integer, it's a factor.

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โˆ™ 2015-07-31 18:12:09
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How you test whether 7 is a factor of 291?
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How do you test whether 7 is a factor of 291?

Divide 7 into 291. If the result is an integer, 7 is a factor.


How would you test whether 7 is a factor of 291?

Divide 7 into 291. If the answer is an integer, it's a factor.


How would you test to see whether 7 is a factor 291?

Divide 7 into 291. If the answer is an integer, 7 is a factor.


How would you test to see whether 7 is as factor of 291?

Divide it. It isn't.


How will you test to see whether 7 is a factor or 291?

I would divide it. It doesn't come out even. It's not a factor.


How would you tested to see weather 7 is a factor of 291?

There isn't an easy test for 7. You have to divide it. 7 is not a factor of 291.


How would you test to see if 7 is a factor of 291?

7 doesn't have an easy test. But when I see that 291 is made up of 280 + 11, I know that 7 is not a factor.


How would you test if 7 is a factor of 291?

Divide 291 by 7 and see if you get a whole number or is there a remainder. If it is not a whole number, then it is not a factor. 7 goes into 291 41 times with a remainder of 4, so it is not a factor.


How would you test to see wether 7 is a factor of 291?

Divide 7 into 291. If it comes out evenly, it's a factor. It doesn't, so it's not.


How do you explain 7 the factor of 291?

I can't explain it. 7 is not a factor of 291.


What factor is paired with 7 to give 291?

None. 291 is not divisible by 7 and so you cant have a whole number factor pair with 7


How can you check if 7 is a factor of 291?

Divide 7 into 291. If the answer is an integer, seven is a factor. It isn't.

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