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The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18

So the probability of not getting 11 with 1 throw of the dice is 17/18.

Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456...

So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954

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Q: If 11 is the sum and you roll two dice what is the probability of getting 11 if you toss the dice 54 times?

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1 out of 6 times,or 16.67% probability.

It is 0.9034, approx.

One.

1 in 36

0.3 * 0.3 = 0.09

The probability of getting a sum of 2 at least once is 0.8155

1:6

It is 2/6 = 1/3

In one roll the probability is 1/36.

The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.

There is a 50% chance.

It is 5/6.

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