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The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18

So the probability of not getting 11 with 1 throw of the dice is 17/18.

Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456...

So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954

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โˆ™ 2010-04-25 21:38:57
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Q: If 11 is the sum and you roll two dice what is the probability of getting 11 if you toss the dice 54 times?
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