3x - 1 = 11 so 3x = 12 so x = 4, so x^2 + x = 16 + 4 = 20 3x=12 so therefore x=4 x2 + x = 16 + 4 = 20
It is a linear equation in one variable, x. Oh, I suppose you want the solution? 2x + 33 = 4x + 11 Subtract 2x from both sides: 33 = 2x +11 Subtract 11 from both sides: 22 = 2x Divide both sides by 2: 11 = x
If 3x + 3 = 2x + 6 then 3x - 2x = 6 - 3 x = 3
2x+3x = 5x
If 5 x equals 9 plus 2x then x equals?
(The original question was misphrased.) 4x-7 = 2x+5 resolves as 2x-7 = 5 2x = 12 x = 6
2x + 33 = 4x + 11 -11 -11 2x + 22 = 4x -2x -2x 22 = 4x Divide each side by 4 x = 5.5
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
How do you add 2x plus 3y equals 18 in 5x-y equals 11
2x-11
I suspect the answer depends on the value of t.
2x+5=11 2x=6 x=3
-2x+13y=11 13y=2x+11 y=2x/13 + 11/13
2x+3 = -11 2x = -11-3 2x = -14 x = -7
It is an equation and the value of x is 1
4
If: -2x+5 = -17 Then: x = 11
7