I guess that would be power (energy per unit time), i.e. Joules per second, a.k.a. Watts.I guess that would be power (energy per unit time), i.e. Joules per second, a.k.a. Watts.I guess that would be power (energy per unit time), i.e. Joules per second, a.k.a. Watts.I guess that would be power (energy per unit time), i.e. Joules per second, a.k.a. Watts.
Watts are a measure of power, Joules are a measure of energy. The energy is equal to the power times the time. So if you have a power of 5 watts running for 7 seconds, that is 5x7 Joules of energy, or 35 Joules. Looked at another way, power measures how fast energy is converted. So 35 Joules converted in 7 seconds would be 5 watts of power, but it would need 35 watts to convert that energy in 1 second.
Energy: joulesPerhaps you mean power: that would be joules/second = watts Intensity is measured in watts per square meter.
Watts is a unit of power; Joules is a unit of energy. Watts means Joules/second, so you would need to know how long a machine that uses 36 watts (for example, certain light-bulbs) is used.36 watts is simply 36 Joules per second; this is the same as 2160 Joules per minute, or 129,600 Joules per hour.Since the electricity bill is measured in kWh instead of Joule (1 kWh = 3,600,000 Ws = 3,600,000 Joule), you might also say that a device that uses 36 watts uses 0.036 kWh every hour.
joules/second = watts on a one-to-one basis. watts = volts X amps, or more appropriately to this question, amps = watts/volts. You would need to know both the wattage and the voltage of the system in question to "convert joules to amps." you know the wattage, since you know the joules(per second). just establish the voltage, and you can solve for amps.
Is it not....... energy = watts x seconds so assuming this is only over the period of 1 second it would be 491600.6 joules.....
If one were to do one hundred Joules of work in five seconds, he/she would have a power output of 20 Watts.
1 litre through 1 degree C is 1000 calories, equal to 4200 Joules of energy. The power in watts measures how quickly that happens, so that 4200 watts would do it in 1 second, but 100 watts would take 42 seconds.
100 watts means 100 Joules/Second. So in 24 hours, the bulb would use 24*60*60*100 Joules. so that's 8,640,000 joules
Power is work per time, joules per second. So Power would be the rate at which work can be performed.
Efficiency here would be power out divided by power in. Energy out is 38,000 Joules. A joule is a watt X second. The toaster is on for 120 seconds. So that 316.66... watts power over the time period t(which doesn't matter). 316.66... watts/ 330 watts = 0.95959.... efficient or 96%.
Watts aren't consumed per hour, as Watts are defined as joules per second. The wattage of a described unit would be 12 times .5, or 6 watts.Ê
It isn't. Energy is measured in Joules or sometimes Watt-hours. The quantity that is measured in Watts is the power, that is, the rate at which energy is produced, the amount of energy supplied per second.The Watt is the international standard unit of power (that is, of the rate at which energy is supplied, transferred, used, or dissipated). The International System of Units (Système international d'unités) is designed so that the units work well together, so Watts are the easiest units of power to use when you are working with current in Amperes, electrical potential in Volts, energy in Joules, etc. Because of this, it is very easy to work out how much power is delivered in Watts if you know the e.m.f. in Volts and the current in Amperes: multiply Volts times Amperes to get Watts. And then you can go on to an easy conversion to energy: Watts times seconds equals Joules.The alternative to using Watts as a unit of power would be horsepower, which is much harder to convert when considering current and voltage.
If it's to lift 30 kg, it depends how far it is to be lifted and how quickly the lift takes to complete. To lift 30 kg through 10 metres requires 30 x 9.8 x 10 joules of energy, that is 3000 Joules. To do that in 10 seconds needs 300 watts, which would be about half a horse power motor. To do it in 5 seconds the power would be 600 watts - a 1 horse power motor.
A power of 10 kW or 10,000 watts means that 10,000 Joules of energy is converted every second. In 1 hour the energy expended is 10 kilowatt-hours which would appear as 10 units on the electricity bill.
I would have to guess, 100 watts. Power consumed is equal to P I E. P = Amps (I) X Volts (E). Power is measured in watts, or typically, as read on your energy bill, Kilowatts (kw, where 1 Kw = 1,000 watts). So, 100 watts/120V (which is the typical American system) = 0.833 amp (I). Your typical power meter, by which the power company reads your monthly bill, measures amps. Also, 100 watts is 1/10 Kw, or 0.10 kw/hourAnswerFirst of all, you do NOT consume power; you consume energy. Energy is measured in joules, so power is measured in joules per second, which is given a special name: the watt.So there is no such things as 'watts per hour', as this would mean 'joules per second per hour' which, obviously, is nonsense!So, your question should ask, "How much energy is consumed by a 100-W lamp in one hour?" Well, if one watt represents one joule per second, then the lamp will consume 100 x 60 joules in one minute and, therefore, 100 x 60 x 60 joules in one hour. That is, 360 000 joules.Electricity companies usually measure energy in kilowatt hours, rather than in joules. A kilowatt hour is defined as "the energy consumed, in one hour, at a rate of one kilowatt'. You can think of a kilowatt hour simply as being a very big joule! Since 100 W is 0.1 kW, we can therefore say that the lamp must consume 0.1 x 1 = 0.1 kilowatt hours during a period of one hour.
60 watts = 60 joules per second5,400 joules = (5,400 / 60) = 90 seconds, at the rate of 60 wattsBut we must disagree with the language of the question.At the rate of 60 watts, it takes 90 seconds to use 5,400 joules of energy. But no work is done.The energy is converted into electromagnetic energy, in the form of heat and light, and it'scarried away from the light bulb by the E&M radiation.
5 HP MOTOR WOULD CONSUME ENERGY OF 1342800 JOULES IN AN HOUR.EXPLANATION :-1 HP = 746 WATTSTHEREFORE 5 HP = 3730 WATTS.= 373O Joules/sec (since 1WATT= 1 Joules/sec)=3730 x 3600= 13428000 Joules/ hour.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
A force of 100 newtons acting through a distance of 10 metersresults in 1,000 joules of energy transferred.If it all takes place in 10 seconds then the average rate of energytransfer (power) during that interval is(1,000/10) = 100 joules per second = 100 watts.
Foot-candle is a unit of light intensity, not of power like watts. The power would vary, depending on the color of the light.Foot-candle is a unit of light intensity, not of power like watts. The power would vary, depending on the color of the light.Foot-candle is a unit of light intensity, not of power like watts. The power would vary, depending on the color of the light.Foot-candle is a unit of light intensity, not of power like watts. The power would vary, depending on the color of the light.
It would be useful to know just how "low-watt" they are, in other words, exactly how many watts they use. Once you have that, use the formula: energy = power x time. If power is in watts and time in seconds, the energy will be in joules.
2a to the second power. If you combine the like terms, (a to the second power + a to the second power), it would be the same as 2a to the second power.
It depends on how fast you want it lifted. A low-power motor would lift it slowly, while a high-power motor would lift it quickly. 1 kg has a weight of 9.806 Newtons, so 27 kg has a weight of 265 Newtons. Lifting that through 1 metre needs 265 joules of energy. If the motor did that in 1 second it would be supplying 265 watts, if it took 10 seconds it would be supplying one tenth of that, 26.5 watts. The motor would need to supply about 20% more power to overcome friction and it would take about another 25% more electrical power again to overcome the losses in the motor.
Yes it can but it is a bit more complicated then that. The motor that is rated at 100 Watts will draw 100 watts electrical power, but will only output 70-80% of that in mechanical power. So in order to get 100 watts back out you would have to put in ~120 watts of mechanical power to get 100 watts electrical back out.