Wiki User
∙ 11y ago-14 J/Mol
Wiki User
∙ 11y agoTo find the enthalpy change of the reaction (ΔH) in joules per mole, you would divide the energy produced (84 J) by the number of moles of the compound (6 moles). ΔH = 84 J / 6 moles = 14 J/mol.
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
84 J/6 moles = 14 J/mole = ∆H
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
For the reaction 2Al + 6HCl → 2AlCl3 + 3H2, you need 3 moles of H2 for every 1 mole of Al. Thus, to produce 4 moles of H2, you would need 4/3 moles of Al.
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
84 J/6 moles = 14 J/mole = ∆H
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
-14 J/mol
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
For the reaction 2Al + 6HCl → 2AlCl3 + 3H2, you need 3 moles of H2 for every 1 mole of Al. Thus, to produce 4 moles of H2, you would need 4/3 moles of Al.
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
Carbon dioxide is the limiting reagent.
This chemical equation represents the reaction of potassium with water to produce potassium hydroxide and hydrogen gas. Two moles of potassium react with two moles of water to produce two moles of potassium hydroxide and one mole of hydrogen gas.