ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6
5.3 = 2x so x = 5.3/2 = 2.65
yes because ab plus bc is ac
No. A times B = AB
That depends on the value of CD and the perimeter of the quadrilateral out lined in the question
The existence of the additive inverse (of ab).
the midpoint of AB.
C minus B equals AB
ab=1a+1b a is equal to either 0 or two, and b is equal to a
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
You need to provide more information in order to answer this question. However, you need to use either Subsitution or Elimination. Substitue the equation of Line AB into the equation of Line CD. E.g. Line AB y=2x Line CD y=3x+2 2x=3x+2 3x-2x=-2 x=-2 Sub x=-2 into either equation y=2(-2) y=-4 Therefore, the point of intersection is (-2, -4).
No, A+B is left as A+B AB would be A x B
An exothermic chemical reaction.
If you do not assume that "plus" is commutative, all that can be said that it is equal to A plus B.
Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.
i think its ABC and if that not right ask a teacher for the answer
144 Formula: c= (a2)+(ab)
between A and B