Endpoints: A (-2, -4) and B (-8, 4)
Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Length AB is 17 units
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
4 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Length AB is 17 units
Using the distance formula the length of ab is 5 units
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
we can create a graph with the x-axis representing the horizontal values and the y-axis representing the vertical values. let's determine whether the line segments AB and CD are congruent. The length of line segment AB can be calculated using the distance formula: AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) For AB(0, 1) and CD(4, 1), the length of AB is: AB = sqrt((4 - 0)^2 + (1 - 1)^2) = sqrt(16 + 0) = sqrt(16) = 4 For CD(1, 2) and CD(1, 6), the length of CD is: CD = sqrt((1 - 1)^2 + (6 - 2)^2) = sqrt(0 + 16) = sqrt(16) = 4 Since the length of AB is equal to the length of CD (both are 4 units), we can conclude that line segments AB and CD are congruent.
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
12
4 units
(x+3)2 + (y+4)2 = 4
5 [3-4-5 triangle]