Using Pythagoras
Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
5 [3-4-5 triangle]
2*sqrt(34), or approximately 11.7 I assume you are giving the x,y coordinates in the problem. In that case, you use the Pythagorean theorem(with the distance between the points along the x-axis and the distance between the points along the y-axis as the length of the legs and the distance between the points as the distance of the hypotenuse) to determine length: length=sqrt((x1-x2)2+(y1-y2)2)=sqrt(((-4)-2)2+(5-(-5))2)=sqrt((-6)2+(10)2)=sqrt(136)=2*sqrt(34), or approximately 11.7
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Length AB is 17 units
Using the distance formula the length of ab is 5 units
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
we can create a graph with the x-axis representing the horizontal values and the y-axis representing the vertical values. let's determine whether the line segments AB and CD are congruent. The length of line segment AB can be calculated using the distance formula: AB = sqrt((x2 - x1)^2 + (y2 - y1)^2) For AB(0, 1) and CD(4, 1), the length of AB is: AB = sqrt((4 - 0)^2 + (1 - 1)^2) = sqrt(16 + 0) = sqrt(16) = 4 For CD(1, 2) and CD(1, 6), the length of CD is: CD = sqrt((1 - 1)^2 + (6 - 2)^2) = sqrt(0 + 16) = sqrt(16) = 4 Since the length of AB is equal to the length of CD (both are 4 units), we can conclude that line segments AB and CD are congruent.
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
12
4 units
(x+3)2 + (y+4)2 = 4
5 [3-4-5 triangle]