25.2 C
1600
THE ANSWER IS 62.8 DEGREES.....
42.3 Celsius
1.83
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
1600
If coffee and milk have the same thermal coefficient then: (15*22 + 185*86)/200 = 81 (81,2 rounded off due to significant digits)
$1.20 gst was added to a $12 bill what is the final total
In liters, gasoline makes up about 73 liters of the final 170, diesel and heating oil make up about 40 liters, while kerosene-type jet fuels make up about 15.5 liters.
40 degree
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
42.3 C
In tournaments, at the end of the round it is added to the final sanctioned score.
THE ANSWER IS 62.8 DEGREES.....
this is just a guess because both are mostly water, you would expect that the immediate final temperature would be 5/6 the way between 11 and 910C. So ~77.50C. Though because the mixing vessel is not warmed to this temp (heat capicity of calorimeter) along with the room temp playing a role, it will in practice be lower
42.3 Celsius
It would be -221.7 deg C.