It has 6 vertices.
There is no such convex polyhedron in normal geometries because it does not satisfy the Euler characteristic. That requires that Faces + Vertices = Edges + 2
If the object is a convex polyhedron, then, by Euler's characteristics, it should have 23 faces.
There is not a polyhedron with the given number of faces, edges and vertices.
It is a triangular prism that has 5 faces, 6 vertices and 9 edges
The numbers in the question do not satisfy the Euler characteristic so there cannot be such a [convex] polyhedron.
There is no such convex polyhedron in normal geometries because it does not satisfy the Euler characteristic. That requires that Faces + Vertices = Edges + 2
If the object is a convex polyhedron, then, by Euler's characteristics, it should have 23 faces.
A polyhedron has 30 edges and 12 vertices. How many faces does it have
There is not a polyhedron with the given number of faces, edges and vertices.
A sphere is not a polyhedron because it has no edges, no vertices and no flat faces The word 'polyhedron' means many faces.
A polyhedron must have at least 4 faces, at least 4 vertices and at least 6 edges.
It is a triangular prism that has 5 faces, 6 vertices and 9 edges
For all polyhedra: vertices + faces = edges + 2 The given fact is: edges = vertices + 10 → vertices + faces = vertices + 10 + 2 → faces = 12
For a simply connected polyhedron,Faces + Vertices = Edges + 2
The numbers in the question do not satisfy the Euler characteristic so there cannot be such a [convex] polyhedron.
No, F + V = E + 2That's Euler's polyhedron formula (or Theorem). For a normal 3-d polyhedron to exist it must conform to that equation.
Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.