1 out of 20
this is because there are 20 numbers in total, and there is only one 7 in there. (Assuming that there is the same probability for each number to be chosen, and that 17 is excluded as an affirmative outcome)
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
The probability is 8/20.
The probability that any given donor is a universal donor is 0.072.We need the probability that the number of universal donors in this group of 20 is not zero or one.Probability of getting zero universal donors: ( 1 - 0.072 )^20 = 0.224367Probability of getting one such donor: 0.348156 (given by the binomial probability density function: probability of one success in 20 trials with p=0.072)Total: 0.224367 + 0.348156 = 0.572523, the probability of zero or one donorsBut we want 1 - 0.572523 = 0.427477, the probability of getting two or more such donors.^ stands for 'to the power of'
The answer depends on the number of choices available for each question.
P( a student getting an A) = 5/20=1/4 There are 3 students. The probability that all three got an A is (1/4)(1/4)(1/4)=1/64.
40%
There are 20 numbers from 20 through 39, and 4 of them are prime (23, 29, 31, 37), the probability is 4 in 20 or 0.20.
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
There are 12 composite (and 8 primes) in the first twenty whole numbers. So the probability of randomly choosing a non-prime is 12/20 or 60%.
It depends on what variable the probability ratio was for! The random variable could have been the number of heads minus the number of tails, for example.
The probability is 8/20.
No, a probability must needs be a number between 0 and 1.20% might be a probability, though - since that is equivalent to 0.2.
The result of tossing the coin would not affect which number was selected. So we say that these two events are independent. We can therefore assess the probability of each of them separately and then multiply the two probabilities together for a final result. Probability of getting tails: 1/2 (since there is one way of getting heads out of two possibilities) Probability of getting zero: 1/10 (since there is one way of getting zero out of ten possibilities) Overall probability: 1/2 x 1/20 = 1/20
The probability that any given donor is a universal donor is 0.072.We need the probability that the number of universal donors in this group of 20 is not zero or one.Probability of getting zero universal donors: ( 1 - 0.072 )^20 = 0.224367Probability of getting one such donor: 0.348156 (given by the binomial probability density function: probability of one success in 20 trials with p=0.072)Total: 0.224367 + 0.348156 = 0.572523, the probability of zero or one donorsBut we want 1 - 0.572523 = 0.427477, the probability of getting two or more such donors.^ stands for 'to the power of'
The answer depends on the number of choices available for each question.
P( a student getting an A) = 5/20=1/4 There are 3 students. The probability that all three got an A is (1/4)(1/4)(1/4)=1/64.
The probability, in a single random selection, is 1/20 or 0.05