No. Consider 6 itself or 18.
Not always because 18 is divisible by 2 and 6 but not by 12
Yes, because 12 is divisible by 2 and 6.
lol yeah it is i think
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
Since 5232 is divisible by both 2 and 3, it is divisible by 6.A number must be divisible by both 2 and 3 to be divisible by 6.The number 5232 is even, so it is divisible by 2.If you add the individual digits in the number (5+2+3+2=12) you get a number that is divisible by 3, meaning the original number (5232) is also divisible by 3.
Not always because 30 is divisible by 2 and 6 but not by 12
Not always because 18 is divisible by 2 and 6 but not by 12
Answer is 48. Step-by-step instructions: Factors of 4 = 1,2,4. Factors of 12 = 1,2,3,4,6,12. So, let's see 12's first 4 multiples. = 12,24,36,48. Now, let's check 48's Factors. = 1,2,3,4,6,12 It's Factors have both 4 and 12. So, it is the number this is divisible by Both 4 and 12.
Yes, because 12 is divisible by 2 and 6.
no...for example 18 18 divided by 3=6 18divided by 2=9 18 cant be divided by 12
If a number is divisible by both three and four, it's divisible by twelve.
The smallest whole number divisible by both 8 and 12 is 24.
lol yeah it is i think
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
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