if a polygon has 560 diagnose how many vertices does it have
35 sides
A 3-sided polygon is a triangle. There is no diagonal for that shape since all non-adjacent vertices share a line segment!
19. sides=vertices
A polygon has as many vertices as it has sides and so in this case it will have 20 vertices.
38 diagonals
50 since there are 100 vertices ("gons") and it takes two vertices to connect a diagonal, there will be 50 diagonals.
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
A polygon with n vertices has n*(n-3)/2 diagonals. So an octagon has 8*5/2 = 20 diagonals. Of those 20 diagonals, 8 are the principal diagonals, the ones joining a pair of opposite vertices
Using the formula 0.5(n^2 -3n) whereas n is number of sides, altogether there are 104 diagonals in a 16 sided polygon
A 3-sided polygon is a triangle. There is no diagonal for that shape since all non-adjacent vertices share a line segment!
10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
That polygon is called a "triangle". It has no diagonals.
how many diagonals are there iin a polygon of 11 sides
There are 90 diagonals in a 15-sided polygon.
An 11 sided polygon has 44 diagonals.
A four-sided polygon has two diagonals.
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.