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If a rectangle has a perameter of 52cm and width of 12cm what is the length?
Wiki User
∙ 14y ago
Perimeter of a rectangle = 2 x length + 2 x width.
52 = 2l + 2 x 12 = 2l + 24 (Where l is the length)
2l = 52 - 24 = 28
length = 28/2 = 14 cm
Wiki User
∙ 14y ago
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1 A rectangle is 14 cm long and 10 cm wide If the length is reduced by x cms and its width is increased also by x cms so as to make it a square then its area changes by?
Answerfirst you have to make it a square by subtracting 2cms from the length and adding 2cms to the width. That will make it equal to 12cm. The area for the rectangle was 140cm then it increased by 4 because 12cm * 12cm is 144cm. so x = 2 and the area increases by four.
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1 A rectangle is 14 cm long and 10 cm wide If the length is reduced by x cms and its width is increased also by x cms so as to make it a square then its area changes by?
Answerfirst you have to make it a square by subtracting 2cms from the length and adding 2cms to the width. That will make it equal to 12cm. The area for the rectangle was 140cm then it increased by 4 because 12cm * 12cm is 144cm. so x = 2 and the area increases by four.
What kind of shape has 25cm width and 12cm height?
A rectangle or perhaps a parallelogram
The perimeter of a rectangle is 16 times the width the length is 12cm more than the width what are the length and width of the rectangle?
length 14cm, width 2cm This is worked out by finding the following equations: perimeter = 16 x width length = width + 12 Then working out 16 x width = 2 x (width + 12) + 2 x width -> 14 x width = 2 x (width + 12) -> 14 x width = 2 x width + 24 -> 12 x width = 24 -> width = 2cm Since lendth = width + 12, length = 14cm
