Being a layman, this will be a lay answer until an expert, or skydiver improves it. As I recall, the acceleration of gravity is 32 feet per second per second. My calculations suggest that in a vacuum, the skydiver's velocity would be 288 feet per second, or 196 miles per hour. However, since the diver is falling through the air of the atmosphere, there is frictional resistance, resulting in what is called drag, which limits the falling speed. Depending on the weight of the diver, the size and amount of loose clothing the diver wears, there will be a limited maximum speed of fall, refered to as terminal velocity, generally in the range of 120 to 125 miles per hour.
Nearly a hundred feet per second, but it would depend on your body position. Terminal velocity in the 'flat position' is 192 feet per second (120MPH), but it is possible to go muchfaster if you know what you're doing (>340MPH)
187 miles per hour.
To calculate this, you divide the change in velocity, by the time.
TrUe <3 (=
Acceleration due to gravity is 9.8m/s/s, which is the same as 9.8m/s2. An acceleration of 9.8m/s/s means that with each passing second, the velocity of the skydiver increases by 9.8m/s. Therefore, after two seconds. a skydiver's velocity would be 19.6m/s. The acceleration will continue at 9.8m/s/s until the skydiver reaches terminal velocity, at which point the weight of the skydiver and the air resistance will be balanced, so the net force acting on the skydiver will be zero, at which point there will be no further acceleration.
Neglecting air resistance his velocity after 1 second will be 9.81 m/sec or 32.2 ft/sec.
We'll assume you mean 2 seconds AFTER he's jumped from the plane. A good estimate would be 9.8m/s times 2 (9.8m/s/s times 2 seconds -- the standard value of the acceleration due to gravity). In two seconds, the velocity would be low enough that air resistance could probably be ignored for purposes of answering your homework. So try 19.6 m/s, unless your teacher gave your data on the air resistance of the sky diver.
Velocity increases after 5 seconds
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
After just over three and a quarter seconds.
Velocity is derived by dividing displacement with time in seconds
The duration of The Skydivers is 1.25 hours.
The velocity = (location at 40 seconds - location at 20 seconds)/20 in the direction in which the object is moving.