The diameter of the circle is congruent to the length of the diagonal of the inside square. If you know the length of one side of the square, you can use pythagorean's theorem to solve for its diagonal (hypotenuse) and thusly the square's diameter.
A square with an area of 2 m2 has sides of sqrt(2) m. The diameter of the inscribed circle is, therefore sqrt(2) m. The radius is sqrt(2)/2 m The area of a circle with radius sqrt(2)/2 is pi*[sqrt(2)/2]2 = pi*2/4 or pi/2 = 1.5708 m2
The circle's diameter is 5.998 cm
If the area of a circle is 20 square inches the diameter is: 5.046 inches.
A 72-inch diameter circle has an area of: 28.3 square feet.
The area of a circle with a diameter of 6.5 is: 33.18 square units.
Its diameter is congruent to a side of square.
The sides of the Square.
The diameter of the circle equals the length of a side of the square
the side of the square
The diagonal of the square.
The formula for the area of a circle is pi x radius2. The radius is half the diameter, and the diameter of an inscribed circle is the same as the length of a side of the square.The formula for the area of a circle is pi x radius2. The radius is half the diameter, and the diameter of an inscribed circle is the same as the length of a side of the square.The formula for the area of a circle is pi x radius2. The radius is half the diameter, and the diameter of an inscribed circle is the same as the length of a side of the square.The formula for the area of a circle is pi x radius2. The radius is half the diameter, and the diameter of an inscribed circle is the same as the length of a side of the square.
The diameter of the circle is equal to the diagonal of the square, or the (side of the square) times the (square root of 2).
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
A circle with a diameter of 2 is the guiding cynosure when Pi is the square of all possible circles: If the square root of Pi defines the side of a square and that square can be inscribed within a circle or enclose a circle, then the diameters of all possible circles between the largest and smallest include the circle of which Pi is its perfect square (a diameter of 2).
Yes.
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
yes