## 1. Subba Rao started work in 1995 at an annual salary of Rs 5000 and received an increment of Rs 200 each year. In which year did his i

Question

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## Answers ( )

Answer:2005

Step-by-step explanation:a = 5000

n = ?

d = 200

tn = a + (n – 1)d

7000 = 5000 + (n – 1) 200

2000 = 200n – 200

2200 = 200n

n = 11

therefore

1995 + 11 – 1

year = 2005

Given:-To find:-Solution:-Hence,in11th year his income reach Rs 7000.MoreInformation:–Arithmeticprogression:–Relatedtoarithmeticmean:–➝If a,A,b are in AP we can say that A is the arithmetic mean between a and b and it is abbreviated of AM.