IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
Whatever the wavelength and frequency happen to be, their product is always equal to the speed.
This generally happens when a wave moves from one medium into another.Now, the velocity (v) of a wave (mechanical and electromagnetic) is equal to the product of its frequency (f) and wavelength (λ).So, v = f x λThat means if frequency is constant, the wavelength is directly proportional to the velocity.So, if the speed of the wave increases (while frequency remains the same), the wavelength will also increase.
it would become longer
It will simply double.Wavelength = Velocity / Frequencyor in your caseVelocity = Frequency x wavelength+++Except that would demand unusual conditions.'Doubling of speed can only happen if the wave passes from its first medium to another of very different properties. Any given wave motion has a speed constant for any medium itself that is able to transmit it.'For sound, the speed is approximately 340m/s in air, 1500m/s in water (varying very slightly with the density of the air or water). This is irrespective of frequency hence irrespective of wavelength.'So for a single medium, as the speed cannot change (ignoring small changes due to density changes) the wavelength is always inversely proportional to frequency only.
If both dimensions are doubled then the area is quadrupled. This is true of any geometric shape.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
Whatever the wavelength and frequency happen to be, their product is always equal to the speed.
If the frequency stays the same, then the wavelength stays the same.
The wavelength would double.
This generally happens when a wave moves from one medium into another.Now, the velocity (v) of a wave (mechanical and electromagnetic) is equal to the product of its frequency (f) and wavelength (λ).So, v = f x λThat means if frequency is constant, the wavelength is directly proportional to the velocity.So, if the speed of the wave increases (while frequency remains the same), the wavelength will also increase.
There are several ways to calculate the frequency of light emitted or absorbed by different chemicals, and they depend on what you already know. For example, if you know the energy of the particle, then you can calculate frequency from E = planck's constant x frequency and solve for frequency. If you happen to know the wavelength, then you can use C = wavelength x frequency and solve for frequency (where C = speed of light).
It would change, depending on how much the frequency and the wavelength changes. It varies based on v = fλ.
the wave length will increase
For any electromagnetic wave, from the highest gamma wave to the lowest radiowave, the product of (frequency) times (wavelength) is always the 'speed of light'in whatever substance the waves happen to be waving along at the moment.So if the wavelength of any of them should decrease, for whatever reason, itsfrequency would have to increase, in order to keep the product constant.
The resulting waveform will have the same frequency as both components although the amplitude will be doubled.
No. In order to be coherent, the light waves have to be in phase and stay in phase, and the only way for that to happen is for them to have the same wavelength and frequency.
The product of (wavelength) times (frequency) is always the same number ... the wave's speed. So if one of them doubles, the other one must drop by half.